This is for Algebra 2 and I need help ASAP! 22pts if you show work and explanation Describe and correct the error in solving the equation.
Accepted Solution
A:
Answer:Part 41) The solutions are 3 and 1Part 42) The solution is 2 onlyStep-by-step explanation:Part 41) we have[tex]\left|5x-9\right|=x+3[/tex]step 1Find the first solution (case positive)[tex]+(5x-9)=x+3[/tex][tex]5x-x=3+9[/tex][tex]4x=12[/tex][tex]x=3[/tex]step 2Find the second solution (case negative)[tex]-(5x-9)=x+3[/tex][tex]-5x+9=x+3[/tex][tex]5x+x=9-3[/tex][tex]6x=6[/tex][tex]x=1[/tex]thereforeThe negative case was resolved incorrectlyThe solutions are 3 and 1Part 42) we have[tex]\left|n-7\right|=3n-1[/tex] step 1Find the first solution (case positive)[tex]+(n-7)=3n-1[/tex] [tex]3n-n=-7+1[/tex][tex]2n=-6[/tex][tex]n=-3[/tex]VerifyFor n=-3substitute[tex]\left|-3-7\right|=3(-3)-1[/tex] [tex]\left|-10\right|=-9-1[/tex] [tex]10=-10[/tex] ------> is not truetherefore[tex]n=-3[/tex] -------> is not a solutionstep 2Find the second solution (case negative)[tex]-(n-7)=3n-1[/tex][tex]-n+7=3n-1[/tex][tex]3n+n=7+1[/tex][tex]4n=8[/tex][tex]n=2[/tex]thereforeThe solution is 2