Q:

how do you find the perimeter of a parallelogram​

Accepted Solution

A:
There may be a simpler way to solve this question, however if you are currently learning distance formula, then this may be the correct way to solve it.Answer: DStep-by-step explanation:To find the perimeter of this parallelogram, you would have to find the distance between the coordinates. I would use the distance formula for this question.Distance Formula - [tex]d=\sqrt{(x_2 -x_1)^{2}+(y_2 -y_1)^{2}}[/tex]Ok, let's find the length of side AB.Coordinates of A = (-5, -7)  This will be our second x and y coordinates [[tex]x_2,y2[/tex]]Coordinates of B = (2, -3) These will be our first x and y coordinates   [[tex]x_1,y1[/tex]]Now Substitute Into The Equation -[tex]d=\sqrt{(-5-2)^{2} +(-7-(-3))^{2} }[/tex]Solve/Simplify - [tex]\sqrt{(-5-2)^2+(-7-(-3))^2} \\ \\ \sqrt{(-5-2)^2+(-7+3)^2} \\\\\sqrt{(-7)^2+(-4)^2}\\\\ \sqrt{49+16} \\\\ \sqrt{65}[/tex]Great! We have the first distance for the perimeter.Now let's solve for side CBPoint C = (-1, 2) This will be our second x and y coordinates [[tex]x_2,y2[/tex]]Point B = (2, -3) These will be our first x and y coordinates   [[tex]x_1,y1[/tex]]Substitute and Solve - [tex]\sqrt{(-1-2)^2+(2-(-3))^2}\\\\sqrt{(-1-2)^2+(2+3)^2}\\\\\ \sqrt{(-3)^2+(5)^2}\\\\ \sqrt{9+25}\\\\\sqrt{34}[/tex]Now we have our second distance for the perimeter.Now solve for the other two sides - Because this shape is a rectangle, the parallel lines are the same length.Now, find the perimeter-[tex]\sqrt{65}+ \sqrt{65}+ \sqrt{34} +\sqrt{34}[/tex]That equals about 27.79, rounding up to 27.8Hoped this helped!~