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I need the answer please. Because I think i got mine wrong
4 months ago
Q:
I need the answer please. Because I think i got mine wrong
Accepted Solution
A:
Answer:see explanationStep-by-step explanation:Using the rules of exponents• [tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]• [tex]a^{0}[/tex] = 1• [tex]a^{m}[/tex] × [tex]a^{n}[/tex] ⇔ [tex]a^{(m+n)}[/tex]Given(a)[tex]8^{-2}[/tex] = [tex]\frac{1}{8^{2} }[/tex](b)[tex]\frac{1}{3^{-3} }[/tex] = 3³(c)[tex]6^{-12}[/tex] × [tex]6^{8}[/tex] × [tex]6^{0}[/tex]= [tex]6^{(-12+8)}[/tex] × 1= [tex]6^{-4}[/tex]= [tex]\frac{1}{6^{4} }[/tex]